Tyres traversed
A boy is riding a bicycle from his native place to another town, 300 miles away. During the journey he has used 3 tyres, all of them having traversed the same distance. Now the question is how long each tyre has traversed in miles?
Answer:
200 miles.
If a bicycle is ridden for a mile, then each of the two tyres has travelled a mile. Since the boy has covered 300 miles, the front and back tyres have travelled 300 miles each. that is 600. This number is divided by 3 tyres to arrive at 200, which is the correct distance to be traversed by each tyre. For the algebraically oriented, the following equations hold good.
If you call 3 tyres as 'A', 'B', and 'C' and the actual distance traversed by each tyre as 'x' then
the journey comprises of first travel A and B. Second travel A and C. Third travel B and C.
Therefore 2(A+B+C) = 600. 2(x+x+x)=600. So, x=100. Since each tyre is used 2 times in the travel, it must be 2x100=200 miles.
Answer:
200 miles.
If a bicycle is ridden for a mile, then each of the two tyres has travelled a mile. Since the boy has covered 300 miles, the front and back tyres have travelled 300 miles each. that is 600. This number is divided by 3 tyres to arrive at 200, which is the correct distance to be traversed by each tyre. For the algebraically oriented, the following equations hold good.
If you call 3 tyres as 'A', 'B', and 'C' and the actual distance traversed by each tyre as 'x' then
the journey comprises of first travel A and B. Second travel A and C. Third travel B and C.
Therefore 2(A+B+C) = 600. 2(x+x+x)=600. So, x=100. Since each tyre is used 2 times in the travel, it must be 2x100=200 miles.